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Can #y=2x^2 +2x-8 # be factored? If so what are the factors ?

Answer 1

It is non factorable

2(#x^2# + x - 4)

At this point, it is obvious that it is non factorable since there are no two integers that multiply to -4 and that add to + 1. All you can do to factor it is extract a common factor like shown above.

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Answer 2

Jace Anderson

Yes, the quadratic equation ( y = 2x^2 + 2x - 8 ) can be factored. Factoring it gives ( y = 2(x + 2)(x - 2) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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