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Can someone help explain the reasoning behind this question?

Answer 1

Charlotte Aaron

10.12 m

You know the intial velocity (#u#) = #3.2 ms^(-1)#

and, the final velocity (#v#) = #9.7 ms^(-1)#

You also know the acceleration (#a =gsintheta#) = #9.8 *sin25°ms^(-2)=4.14ms^(-2)#

if you apply the conservation of energy, you have:

#v^2=u^2+2as#, where s is the distance travelled.

hence, #s = 1/(2a)(v^2-u^2) = 1/(2*4.14)*(9.7^2-3.2^2)m = 10.12m#

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Answer 2

Nathan Ashcroft

The reasoning behind the question is to assess the understanding of the principle of conservation of momentum and its application in solving problems involving the interaction of objects in motion. This question specifically tests the ability to apply the conservation of momentum equation to determine the change in speed of an astronaut after throwing an object in space.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.