Home > Calculus > Solving Separable Differential Equations

Can someone help clarify this question?

Answer 1

Cameron Alexander

You have followed L'Hospital's Rule and nothing wrong in it.

Probably you are not permitted to follow this rule. You can ask your teacher whether it is permissible or not.

Otherwise you can proceed as shown below. I think this is also known to you .

#lim_(x->-1)((x^3+1)/(x^4-1))#

#=lim_(x->-1)(cancel((x+1))(x^2-x+1))/(cancel((x+1))(x-1)(x^2+1))#

#color(red)[as" "x->-1=> x+1!=0 ]#

#=lim_(x->-1)((x^2-x+1))/((x-1)(x^2+1))#

#=(((-1)^2-(-1)+1))/((-1-1)((-1)^2+1))#

#=((1+1+1))/((-2)(1+1))=-3/4#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Isabella Ackerman

Of course, I'm here to help clarify any questions you may have. Please provide more information or context about the question you need clarification on, and I'll do my best to assist you.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.