Can someone explain on how they derived to the answer of 20.0L?

Question

Mateo Aguilar · Accepted Answer

Work out the number of moles of chlorine gas that yields 75 g of the product, then use the molar volume at STP, 22.4 litres/mol.

With a molar mass of 167.8 g/mol, you have formed 75 / 167.8 = 0.4469 mol of 1,1,2,2-tetrachloroethane. Given that 1 mole of 1,1,2,2-tetrachloroethane is formed for every 2 moles of chlorine gas, according to the equation, in order to form 0.4469 mol of 1,1,2,2-tetrachlorothane, 0.8938 moles of chlorine would have been required. Assuming that one mole of a gas occupies 22.4 liters at STP, 0.8938 moles will occupy 0.8938 x 22.4 = 20.021 liters, or 20.0 liters to the nearest decimal place.

Henry Antrim · Answer

undefined To find out how someone derived the answer of 20.0 L, I would need more context or information about the problem or equation they were solving. Could you provide additional details or clarify the question?