Can someone check my homework?


Answer 1

See below.

Part i)

If we are to assume that the triangle #OSF# is right angled at #ShatOF# the the distance #SF# is found by Pythagoras' theorem:
#SF=sqrt(10^2+12^2)=sqrt(244)=2sqrt(61)#
Rowing at #8kmh^(-1)#
#"time"="distance"/"speed"=(2sqrt(61))/8=1.96color(white)(8)#hrs

closest hundredth

I am not sure where you found the letter "u" in your computation, unless I am overlooking something.

Part ii)

Essentially, this is the same thing:

To row in the direction of S to O

#10/8#hr

To sprint from point O to point F:

#12/14#hr

Time in total:

#10/8+12/14=59/28=2.11color(white)(8)#hrs

closest hundredth

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Answer 2

Of course! Please provide your homework, and I'll be happy to assist you by checking it.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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