# Calculus 2. Is this the right answer?

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The question is: Find the area of the region bounded by #y=xe^(-x^2/2)# and its asymptote. For my final answer, I got an area equal to 1 and I was hoping if someone could tell me if this is correct. Thanks in advance!

The question is: Find the area of the region bounded by

The area is 1.

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Without the specific content of the answer provided, I cannot confirm whether it is correct or not. If you provide the answer, I can evaluate its correctness and provide feedback or corrections if necessary.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you find the area of the region bounded by the curves #y=tan(x)# and #y=2sin(x)# on the interval #-pi/3<=x<=pi/3# ?
- The region is bounded by the given curves #y=0, y=sqrt(4-x^2), 0<=x<=1# is roated about the x-axis, how do you find the volume of the two solids of revolution?
- How do you find the volume of the solid bounded by the coordinate planes and the plane 3x + 2y + z = 6?
- How do you find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes, and one vertex in the plane x+7y+11z=77?
- How would you find the volume bounded by the coordinate planes and by the plane 3x + 2y + 2z = 6?

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