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Calculate the new molarity that results when 250 mL of water is added to each of the following solutions? a. 125 mL of 0.251 M HCl

Answer 1

Noah Aldrich

#1/12\ "M"#

#"Molarity" = "Moles of solute"/"Volume of solution (in litres)"#

Initial moles of solute is

#"n = 0.251 M × 0.125 L = 0.03125 mol"#

New volume of solution #"= 125 mL + 250 mL = 375 mL = 0.375 L"#

New Molarity is

#"Molarity" = "0.03125 mol"/"0.375 L" = color(Green)(1/12\ "M")#

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Answer 2

Caleb Adams

To calculate the new molarity when 250 mL of water is added to a solution, you can use the formula:

M1V1 = M2V2

Where: M1 = initial molarity V1 = initial volume M2 = final molarity V2 = final volume

Given: M1 = 0.251 M (initial molarity of HCl) V1 = 125 mL (initial volume of HCl) V2 = V1 + 250 mL (final volume after adding water)

Substituting the values into the formula:

(0.251 M)(125 mL) = (M2)(125 mL + 250 mL)

Solve for M2:

M2 = (0.251 M * 125 mL) / (125 mL + 250 mL)

M2 = (0.251 * 125) / 375

M2 ≈ 0.0837 M

Therefore, the new molarity of the solution after adding 250 mL of water is approximately 0.0837 M.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.