Calculate the mass of oxygen in a molecule of #"CO"_2# by using percentage composition? please help

Answer 1

#5.3 * 10^(-23)"g"#

The first thing you need to do here is to figure out the mass of oxygen in #1# mole of carbon dioxide. To do that, you must use the compound's molar mass.
Now, carbon dioxide has a molar mass of #"44.01 g mol"^(-1)#. This means that #1# mole of carbon dioxide has a mass of #"44.01 g"#.
You know that #1# mole of carbon dioxide contains
Oxygen has a molar mass of #"16.0 g mol"^(-1)#, so #1# mole of oxygen atoms has a mass of #"16.0 g"#.
This means that if you take #"44.01 g"# of carbon dioxide, you know for a fact that it will contain
#2 color(red)(cancel(color(black)("moles O"))) * "16.0 g"/(1color(red)(cancel(color(black)("mole O")))) = "32.0 g O"#
This means that #"100 g"# of carbon dioxide will contain
#100color(red)(cancel(color(black)("g CO"_2))) * "32.0 g O"/(44.01color(red)(cancel(color(black)("g CO"_2)))) = "72.7 g O"#
Therefore, carbon dioxide has a percent composition of #"72.7%# oxygen, i.e. for every #"100 g"# of carbon dioxide you get #"72.7 g"# of oxygen.

Now, you must determine the mass of oxygen present in a single molecule of carbon dioxide. Start by figuring out the mass of a single molecule of carbon dioxide.

To do that, use Avogadro's constant, which tells you that

#color(blue)(ul(color(black)("1 mole CO"_2 = 6.022 * 10^(23)"molecules CO"_2)))#

So, you know what

#"1 mole CO"_2 = "44.01 g" = 6.022 * 10^(23)"molecules CO"_2#
which means that #1# molecule of carbon dioxide has a mass of
#1 color(red)(cancel(color(black)("molecule CO"_2))) * "44.01 g"/(6.022 * 10^(23)color(red)(cancel(color(black)("molecules CO"_2))))#
# = 7.31 * 10^(-23)"g"#
Now you can use the percent composition of carbon dioxide to find the mass of oxygen present in #1# molecule
#7.31 * 10^(-23) color(red)(cancel(color(black)("g CO"_2))) * "72.7 g O"/(100color(red)(cancel(color(black)("g CO"_2)))) = color(darkgreen)(ul(color(black)(5.3 * 10^(-23)"g O")))#

I'll leave the answer rounded to two sig figs.

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Answer 2

To calculate the mass of oxygen in a molecule of CO2 using percentage composition, you first need to know the molar mass of CO2, which is the sum of the atomic masses of carbon and two oxygen atoms.

The atomic mass of carbon (C) is approximately 12.01 g/mol, and the atomic mass of oxygen (O) is approximately 16.00 g/mol.

So, the molar mass of CO2 is: 1 atom of carbon (C) + 2 atoms of oxygen (O) = 12.01 g/mol + (2 × 16.00 g/mol) = 44.01 g/mol

Now, to find the percentage composition of oxygen in CO2: Percentage composition of oxygen = (Mass of oxygen / Molar mass of CO2) × 100

Mass of oxygen = 2 × 16.00 g/mol = 32.00 g/mol

Percentage composition of oxygen = (32.00 g/mol / 44.01 g/mol) × 100 ≈ 72.72%

Therefore, the mass of oxygen in a molecule of CO2 is approximately 72.72%.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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