Calculate the % composition (by mass) of Mg in Mg3(AsO4)2?

Answer 1

To find the amount of magnesium atoms in the compound, just divide the molar mass of three magnesium atoms by the compound's total molar mass, then multiply the result by 100.

#(3 * "24.3050 g/mol")/"350.7594 g/mol" * 100 = "20.8%"#

This indicates that for every 100 grams of magnesium arsenate, you receive 20.8 grams of magnesium.

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Answer 2

Mateo Aguilar

The molar mass of Mg3(AsO4)2 is 3 × 24.305 = 72.915 g/mol; As: 2 × 74.921 = 149.842 g/mol; O: 4 × 16.00 = 64.00 g/mol. Total molar mass = 72.915 + 149.842 + 64.00 = 286.757 g/mol; Mg's molar mass is 24.305 g/mol. The percent composition of Mg is therefore approximately 8.48%.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.