Calculate the buoyant force of a piece of cork of 8cm3 that floats in water. Density of cork is 207kg/m3. ?

I need the mass, in order to get the volume to apply t to the Buoyancy formula of: B=(W)object=(m)object(g)

Answer 1

#0,0784N#

Any object that is fully or partially submerged in a fluid will buoy upward with a force equal to the weight of the displaced fluid, according to Archimedes' Principle.

#therefore B=rho_(fl) V_(fl) g#
#=1000kg//m^3xx8xx10^(-6)m^3xx9,8m//s^2=0,0784N#

(Assuming that the cork is completely submerged as it floats in the water, and that the density of the water is at standard temperature and pressure)

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 2

Buoyant force = Volume submerged * Density of fluid * Acceleration due to gravity Buoyant force = (8 * 10^-6 m^3) * (1000 kg/m^3) * (9.8 m/s^2) Buoyant force ≈ 0.0000784 N

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Not the question you need?

Drag image here or click to upload

Or press Ctrl + V to paste
Answer Background
HIX Tutor
Solve ANY homework problem with a smart AI
  • 98% accuracy study help
  • Covers math, physics, chemistry, biology, and more
  • Step-by-step, in-depth guides
  • Readily available 24/7