Calculate the amount of heat required to raise the temperature of an 83 g sample of water from 36 c to 69 c ?

Answer 1

#"11 000 J"# of heat energy is required.

Use the following formula:

#q=mcDeltaT#,

where:

#q# is heat energy, #m# is mass, #c# is specific heat, and #DeltaT# is change in temperature. #DeltaT=T_"final"-T_"initial"#

Organize the data:

Known/Given

#m="83 g"#

#c=("4.184 J")/("g"*""^@"C")#

#T_"initial"=36^@"C"#

#T_"final"=69^@"C"#

#DeltaT="69"^@"C"-"36"^@"C"="33"^@"C"#

Unknown

#q#

Solution

Plug in the known/given values and solve.

#q=(83color(red)cancel(color(black)("g")))xx(("4.184 J")/(color(red)cancel(color(black)("g"))*""^@color(red)cancel(color(black)("C"))))xx(33^@color(red)cancel(color(black)("C")))="11 000 J"# (rounded to two significant figures)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.