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Calculate resistance of a bulb and highest current flowing through it having rating of #220V - 100W# ?

Calculate resistance of a bulb and highest current flowing through it having rating of #220V - 100W# .

Answer 1

Amelia Adams

The resistance is #=484Omega#

Apply Ohm's Law

#U=RI#

#"Voltage"="Resistance"xx "Current"#

and

#P=UI#

#"Power"= "Voltage"xx"Current"#

The power is #P=100W#

The Voltage is #U=220V#

The current is #I=P/U=100/220=0.45A#

The resistance is

#R=U/I=220/0.45=484Omega#

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Answer 2

Isabella Alvarez

To calculate the resistance (R) of the bulb, use the formula:

R = (Voltage)^2 / Power

Substitute the given values:

Voltage (V) = 220V Power (P) = 100W

R = (220V)^2 / 100W R = (220 * 220) / 100 R = 48400 / 100 R = 484 ohms

To find the highest current (I) flowing through it, use Ohm's Law:

I = Voltage / Resistance

Substitute the given values:

Voltage (V) = 220V Resistance (R) = 484 ohms

I = 220V / 484 ohms I ≈ 0.455 amps (approximately)

Therefore, the resistance of the bulb is 484 ohms and the highest current flowing through it is approximately 0.455 amps.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.