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Calculate no. Of photons emitted by a 60 watt light bulb in 10 h if a bulb emitted least 6.62 A°?

Answer 1

#7.2*10^21# photons

#6.62 A^@ = 6.62*10^-10 m#

Energy of photon #=hc/lambda# #=(6.626*10^-34(m^2kg)/s*3*10^8 m/s)/(6.62*10^-10m)#

#~~color(red)(3.004*10^-16 #

No.of photons emitted per second: Power of Bulb #divide# Energy of each photon #=color(blue)((60W)/color(red)(3.004*10^-16)#

#=1.997*10^17# photons#/s#

In 10 hours, #=1.997*10^17*60*60*10# #=7.2*10^21# photons

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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