C3H8(g)+5O2(g)→ 3CO2(g)+4H2O(l) (a) In the complete combustion of propane, how many moles of CO2(g) are produced per mole of O2(g)? (b) In the complete combustion of propane, how many moles of H2O(l) are produced per mole of O2(g)?

Answer 1

a) #3/5#

b) #4/5 #

a) Using the mole ratio from the equation, #5# mols of #"O"_2# will produce #3# mols of #"CO"_2#. Therefore, the ratio of #"O"_2# used to #"CO"_2# produced will be #1:3/5#.

b) The same concept as in the previous question. #5# mols of #"O"_2# will produce #4# mols of #"H"_2"O"#. Therefore, the ratio of #"O"_2# used to #"H"_2"O"# produced is #1:4/5#.

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Answer 2

Henry Antrim

(a) 3 moles of CO2(g) are produced per mole of O2(g).

(b) 4 moles of H2O(l) are produced per mole of O2(g).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

C3H8(g)+5O2(g)→ 3CO2(g)+4H2O(l) (a) In the complete combustion of propane, how many moles of&nbsp;CO2(g) are produced per mole of&nbsp;O2(g)? (b) In the complete combustion of propane, how many moles of&nbsp;H2O(l) are produced per mole of&nbsp;O2(g)?

C3H8(g)+5O2(g)→ 3CO2(g)+4H2O(l) (a) In the complete combustion of propane, how many moles of CO2(g) are produced per mole of O2(g)? (b) In the complete combustion of propane, how many moles of H2O(l) are produced per mole of O2(g)?