Balance the following equation? Ca(OH)2 (s) + (NH4)2 SO4 (s) → CaSO4 (s) + H2 O (l) + NH3 (g)
This is simply an acid-base reaction.....where ammonium is the acid....
And thus.....
and so.....
Calcium sulfate is reasonably insoluble....and precipitates from solution as a white powder.
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The balanced equation is:
[ \text{Ca(OH)}_2 \text{(s)} + 2(\text{NH}_4)_2\text{SO}_4 \text{(s)} \rightarrow \text{CaSO}_4 \text{(s)} + 4\text{H}_2\text{O} \text{(l)} + 2\text{NH}_3 \text{(g)} ]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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