At time t = 0 s, a wheel has an angular displacement of zero radians and an angular velocity of +28 rad/s. The wheel has a constant acceleration of -0.50 rad/#s^2#. In this situation, at what time will the wheel come to a halt?

Answer 1

56 seconds later.

We may use the equations of motion for constant angular acceleration to obtain :

#omega_f=omega_i + alphat# #therefore t = (omega_f-omega_i)/alpha=(0-28)/(-0,50)=56 s#
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Answer 2

The wheel will come to a halt when its angular velocity reaches zero. The angular velocity decreases at a constant rate due to the constant acceleration. The final angular velocity is given by the initial angular velocity plus the product of the acceleration and the time taken. Setting the final angular velocity to zero and solving for time gives:

0 = 28 rad/s - 0.50 rad/s^2 * t

28 rad/s = 0.50 rad/s^2 * t

t = 28 rad/s / 0.50 rad/s^2

t = 56 s

So, the wheel will come to a halt at t = 56 seconds.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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