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Assume y varies inversely as x, if y=8 when x=4, how do you find x when y=2?

Answer 1

To find x when y=2, we can use the inverse variation formula: y = k/x.

First, we need to find the constant of variation (k). We can do this by substituting the given values into the formula: 8 = k/4.

Solving for k, we multiply both sides by 4: 32 = k.

Now that we have the value of k, we can find x when y=2. Substituting the values into the formula: 2 = 32/x.

To solve for x, we multiply both sides by x: 2x = 32.

Finally, we divide both sides by 2 to isolate x: x = 16.

Therefore, when y=2, x=16.

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Answer 2

Eli Assouline

#x=16#

#y" varies inversely as "x=>yprop1/x#

#=>y=k/x" where "k" is the constant of proportionality"#

#y=8, x=4#

we have

#8=k/4=>k=8xx4=32#

#:.y=32/x#

#y=2#

#2=32/x=>x=32/2=16#

#x=16#

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Answer 3

Genesis Allen

#x=16#

#"the initial statement is " yprop1/x#

#"to convert to an equation multiply by k, the constant "# #"of variation"#

#rArry=kxx1/x=k/x#

#"to find k, use the condition given for x and y"#

#y=8" when " x=4#

#y=k/xrArrk=xy=4xx8=32#

#"the equation is " color(red)(bar(ul(|color(white)(2/2)color(black)(y=32/x)color(white)(2/2)|)))#

#"when y = 2"#

#xy=32rArrx=32/y=32/2=16#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.