Home > Chemistry > Empirical and Molecular Formulas

Arsenic reacts with chlorine to form a chloride. If 1.587 g of arsenic reacts with 3.755 g of chlorine what is the empirical formula of the chloride?

Answer 1

#AsCl_5#

#"Moles of arsenic"# #=# #(1.587*g)/(74.92*g*mol^-1)=0.0212*mol#.

The expression "Moles of chlorine" is equal to (3.755g)/(35.45gmol^-1) = 0.106mol.

We divide thru by the lowest molar quantity to give #AsCl_5#. This is not chemical you would find in a bottle on a shelf.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Jose Ayala

The empirical formula of the chloride formed from the reaction between arsenic and chlorine is AsCl3.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.