Are those five different ways of receiving Al2(SO4)3 correct?

Question

I tried to do it myself, but I'm not sure if those reactions are correct.

1) Acid + Base
3H2SO4 + 2Al(OH)3 → Al2(SO4)3 + 6H2O

2) Acid + Metal
2Al + 3H2SO4 → Al2(SO4)3 + 3H2

3) metal oxide + metal oxide
3SO3 + Al2O3 → Al2(SO4)3

4) Acid + metal oxide
3H2SO4 + Al2O3 → Al2(SO4)3 + 3H2O

5) Salt + Acid
3H2SO4 + 2Al(NO2)3 → Al2(SO4)3 + 6HNO2

Natalie Anton · Accepted Answer

Yes, they should all work.

The driving force for reactions 1) and 4) is the formation of the weak electrolyte, #"H"_2"O"#. The driving force for reaction 2) is the formation of the gas, #"H"_2#, which escapes into the atmosphere. The driving force for reaction 5) is the formation of the weak electrolyte, #"HNO"_2#. I was initially worried about reaction 3) but, if the reaction is carried out in aqueous media, the #"SO"_3# would react with water to form #"H"_2"SO"_4#, and then you would have reaction 4).

Axel Alvarado · Answer

undefined Indeed, there are five ways to express the chemical formula Al2(SO4)3, depending on how the compound is prepared and its physical state: 1. Al2(SO4)3(s) = Solid form; 2. Al2(SO4)3(aq) = Aqueous solution; 3. Al2(SO4)3(l) = Liquid form; 4. Al2(SO4)3(g) = Gaseous form (unlikely under standard conditions); 5. Al2(SO4)3(cr) = Crystalline form.