Applying Le Chateliers principle, what can you conclude about the change #2CrO_4^(-2) -> Cr_2O_7^(-2)# and its dependence on hydrogen ions, #H^+#?
Adding more hydrogen ions would favour the formation of Removing hydrogen ions would favour the formation of
The equation for net ions is:
based on the principle of Le Chatelier;
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Increasing the concentration of hydrogen ions (H⁺) will shift the equilibrium of the reaction 2CrO₄²⁻ → Cr₂O₇²⁻ to the left, favoring the formation of chromate ions (CrO₄²⁻). Conversely, decreasing the concentration of hydrogen ions will shift the equilibrium to the right, favoring the formation of dichromate ions (Cr₂O₇²⁻).
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The reaction 2CrO4^(-2) -> Cr2O7^(-2) involves the chromate ion (CrO4^(-2)) converting to the dichromate ion (Cr2O7^(-2)). When the concentration of hydrogen ions (H^+) increases, Le Chatelier's principle predicts that the equilibrium will shift to counteract the increase in H^+. Since the reaction consumes hydrogen ions, the equilibrium will shift to the right to consume more H^+ ions. Therefore, increasing the concentration of H^+ ions will favor the formation of Cr2O7^(-2).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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