Answer is 4 which order to solve? #3^0 (5^0  6^1 * 3)/ 2^1# I don't know if I should bring the #6^1# down first or multiply by 3 first.
Following the order of operations, with the parentheses made explicit:
First, perform any operations within parentheses.
Within those parentheses, we treat numerators and denominators as having parentheses around them, and so perform operations within those first.
Perform any multiplication or division, going left to right.
Perform any addition or subtraction, going left to right.
All operations in the numerator have been completed. Moving to the denominator, we have an exponent to evaluate.
All operations within parentheses have been evaluated. Going back, we now evaluate the remaining exponents.
And finally, we perform the remaining multiplication.
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To solve the expression (3^0 (5^0  6^{1} \times 3)/ 2^{1}) correctly, you should follow the order of operations, also known as PEMDAS/BODMAS, which stands for Parentheses/Brackets, Exponents/Orders (i.e., powers and square roots, etc.), Multiplication and Division (from left to right), and Addition and Subtraction (from left to right).

First, evaluate the expressions within parentheses and brackets. In this case, there are none.

Next, deal with exponents. Here, you have exponents involving negative numbers, (3^0), (5^0), and (6^{1}). (3^0) and (5^0) are both equal to 1.

After handling exponents, perform any multiplications and divisions. Since multiplication and division have equal precedence, you should proceed from left to right. Therefore, calculate (6^{1} \times 3) first.

Then, you'll have the expression (3^0 (5^0  \frac{3}{6})/ 2^{1}). Next, calculate (2^{1}), which is equal to (\frac{1}{2}).

Now, you have (3^0 (5^0  \frac{3}{6})/ \frac{1}{2}). Next, evaluate (3^0), (5^0), and (\frac{3}{6}).

Finally, perform the division, followed by any remaining multiplication.
Following this order, you'll eventually arrive at the solution, which is 4.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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