# An object with a mass of #8 kg# is moving at #5 m/s# over a surface with a kinetic friction coefficient of #6 #. How much power will it take to accelerate the object at #3 m/s^2?

The power is

The frictional force

Then,

According to Newton's Second Law

The power is

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To calculate power, use the formula: ( P = F \cdot v ), where ( F ) is the force required, and ( v ) is the velocity. The force can be determined by ( F = m \cdot a_f ), where ( m ) is the mass and ( a_f ) is the net acceleration (considering friction). First, find ( F ) using ( F = m \cdot (a + a_f) ), then substitute into the power formula.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- How much work would it take to push a # 3 kg # weight up a # 11 m # plane that is at an incline of # pi / 6 #?

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