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An object with a mass of #8 kg# is hanging from an axle with a radius of #15 cm#. If the wheel attached to the axle has a radius of #90 cm#, how much force must be applied to the wheel to keep the object from falling?

Answer 1

Emily Abbate

The force is #F=13.1N#

The load is #L=8gN#

The radius of the axle is #r=0.15m#

The radius of the wheel is #R=0.90m#

The effort is #=FN#

The acceleration due to gravity is #g=9.8ms^-2#

Taking moments about the center of the axle

#F*0.90=8g*0.15#

#F=8g*0.15/0.90=13.1N#

The force is #F=13.1N#

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Answer 2

Benjamin Asiedu

The force required is ( \frac{mgr}{R} ), where ( m = 8 \ \text{kg} ), ( g = 9.8 \ \text{m/s}^2 ), ( r = 0.15 \ \text{m} ), and ( R = 0.9 \ \text{m} ). Calculating, the force needed is approximately ( 10.4 \ \text{N} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.