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An object with a mass of #8 kg# is hanging from a spring with a constant of #9 (kg)/s^2#. If the spring is stretched by # 17 m#, what is the net force on the object?

Answer 1

Amelia Adams

The net force is #=74.6N# acting upwards.

Let's resolve in the vertical direction #uarr^+#

mass, #m=8kg#

spring constant, #k=9kgs^-2#

extension of the spring, #x=17m#

#F_1=kx=9*17=153N#

#F_2=-8g=-78.4N#

The net force is

#F=F_1+F_2=153-78.4=74.6N#

The force is acting upwards.

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Answer 2

Elena Albarran

The net force on the object is 153 N.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.