# An object with a mass of #7 kg# is on a surface with a kinetic friction coefficient of # 7 #. How much force is necessary to accelerate the object horizontally at #28 m/s^2#?

I found:

Consider the diagram:

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To find the force required to accelerate the object, use the formula: ( F = m \cdot (a + g \cdot \mu_k) )

Where: ( F ) is the force, ( m ) is the mass of the object, ( a ) is the desired acceleration, ( g ) is the acceleration due to gravity (approximately ( 9.8 , m/s^2 )), ( \mu_k ) is the kinetic friction coefficient.

Substitute the values: ( F = 7 , kg \cdot (28 , m/s^2 + 9.8 , m/s^2 \cdot 7) )

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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