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An object with a mass of #6 kg# is revolving around a point at a distance of #8 m#. If the object is making revolutions at a frequency of #9 Hz#, what is the centripetal force acting on the object?

Answer 1

Julia Aguilar

#F=1.535xx10^5color(white)(x)"N"#

#f=9"Hz"#

This means the time period, i.e the time for 1 revolution is given by:

#T=1/f=1/9"s"#

Speed = distance travelled / time taken so:

#v=(2pir)/T=(2pi8)/(1/9)=144picolor(white)x"m/s"#

The expression for centripetal force is given by:

#F=(mv^2)/r#

#:.F=(6xx(144pi)^2)/8=1.535xx10^5color(white)(x)"N"#

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Answer 2

Isabella Alvarez

The centripetal force acting on the object is 432 N.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.