Home > Physics > Circular Motion

An object with a mass of #6 kg# is revolving around a point at a distance of #8 m#. If the object is making revolutions at a frequency of #7 Hz#, what is the centripetal force acting on the object?

Answer 1

Olivia Askew

#F=9408pi^2" " N#

#m=6" "kg" mass of object"#

#r=8" "m "radius#

#f:7" " Hz" frequency"#

#F=m*v^2/r#

#v=omega*r" ; "v^2=omega^2*r^2#

#F=m*omega^2*r^2/r#

#F=m*omega^2*r#

#omega=2*pi*f" "omega^2=4 pi^2*f^2#

#F=m*4*pi^2*f^2*r#

#F=6*4*pi^2*7^2*8#

#F=9408pi^2" " N#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Charles Aeschliman

The centripetal force acting on the object is 2,688 N.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.