Home > Physics > Circular Motion

An object with a mass of #6 kg# is revolving around a point at a distance of #4 m#. If the object is making revolutions at a frequency of #15 Hz#, what is the centripetal force acting on the object?

Answer 1

William Audy

The centripetal force is #=213183.5N#

The centripetal force is

#F=mromega^2#

The mass of the object is

#m=6kg#

The radius of the circle is

#r=4m#

The frequency of rotation is

#f=15Hz#

The angular velocity is

#omega=2pif=2*pi*15=30pirads^-1#

Therefore,

the centripetal force is

#F=6*4*(30pi)^2=213183.5N#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Amelia Adams

The centripetal force acting on the object is 720 N.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.