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An object with a mass of #6 kg# is revolving around a point at a distance of #2 m#. If the object is making revolutions at a frequency of #12 Hz#, what is the centripetal force acting on the object?

Answer 1

Charles Aeschliman

The centripetal force is #=68219N#

The cetripetal force is

#F=(mv^2)/r=mromega^2#

The mass is #m=6kg#

The radius is #r=2m#

The frequency is #f=12Hz#

The angular velocity is #omega=2pif=2pi*12=24pirads^-1#

So,

#F=6*2*(24pi)^2=68219N#

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Answer 2

Carson Alexander

The centripetal force acting on the object can be calculated using the formula:

Centripetal force = (mass * (angular velocity)^2 * radius)

First, we need to find the angular velocity (ω) using the formula:

Angular velocity = 2π * frequency

Then, plug the values into the centripetal force formula:

Centripetal force = (6 kg * (2π * 12 Hz)^2 * 2 m)

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Answer from HIX Tutor

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