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An object with a mass of #6 kg# is hanging from an axle with a radius of #9 m#. If the wheel attached to the axle has a radius of #18 m#, how much force must be applied to the wheel to keep the object from falling?

Answer 1

Leo Abeyta

The force is #=29.4N#

The load is #L=6gN#

The radius of the axle is #r=9m#

The radius of the wheel is #R=18m#

The effort is #=FN#

The acceleration due to gravity is #g=9.8ms^-2#

Taking moments about the center of the axle

#F*18=6g*9#

#F=(6g*9)/18=29.4N#

The force is #F=29.4N#

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Answer 2

Charles Aeschliman

To keep the object from falling, a force equal to the weight of the object must be applied to the wheel. The weight of the object can be calculated as the mass times the acceleration due to gravity: ( \text{weight} = \text{mass} \times \text{acceleration due to gravity} ). So, the force required would be 6 kg x 9.81 m/s².

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.