An object with a mass of #5 kg# is revolving around a point at a distance of #3 m#. If the object is making revolutions at a frequency of #5 Hz#, what is the centripetal force acting on the object?

Answer 1

Mass #m = 5kg# frequency of rotation #n =5Hz# Radius of circular path #r = 3m# Angular velocity #w = 2pixxn=10pi(rad)/s# Centripetal force #=mw^2r=5xx100pi^2xx3=1500pi^2N#

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Answer 2

Amelia Adams

The centripetal force acting on the object is ( F = m \cdot r \cdot (2\pi f)^2 ), where ( m = 5 , \text{kg} ), ( r = 3 , \text{m} ), and ( f = 5 , \text{Hz} ).

Substituting the given values: [ F = 5 , \text{kg} \cdot 3 , \text{m} \cdot (2\pi \cdot 5 , \text{Hz})^2 ]

[ F = 5 , \text{kg} \cdot 3 , \text{m} \cdot (2\pi \cdot 5)^2 , \text{m}^2/\text{s}^2 ]

[ F = 5 \cdot 3 \cdot 4\pi^2 , \text{N} ]

[ F = 60\pi^2 , \text{N} ]

[ F \approx 592.48 , \text{N} ]

So, the centripetal force acting on the object is approximately ( 592.48 , \text{N} ).

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Answer from HIX Tutor

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