An object with a mass of #5 kg# is on a surface with a kinetic friction coefficient of # 2 #. How much force is necessary to accelerate the object horizontally at #12 m/s^2#?

Answer 1

#=(60+98)=158N#

Net force on the body = its mass(m)#xx#acceleration (a) #5kgxx12ms^-2=60N# Horce of friction = coefficient of friction#(mu)xx# Nomalreaction #mg# #=2xx5xx9.8=98N# So necessary force to be applied #=(60+98)=158N#

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Answer 2

Charlotte Aaron

To find the force necessary to accelerate the object horizontally at 12 m/s^2, you need to use Newton's second law of motion: ( F = ma ). First, calculate the frictional force opposing the motion using the formula: ( f_{\text{friction}} = \mu_k \times N ), where ( \mu_k ) is the coefficient of kinetic friction and ( N ) is the normal force. Then, subtract the frictional force from the force required to accelerate the object. Finally, use the formula ( F = ma ) to find the net force.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.