# An object with a mass of #5 kg# is on a surface with a kinetic friction coefficient of # 3 #. How much force is necessary to accelerate the object horizontally at #6 m/s^2#?

177 N

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Use the formula for horizontal force (( F )):

[ F = m \cdot (a + g \cdot \mu_k) ]

where: ( m ) = mass (5 kg) ( a ) = acceleration (6 m/s²) ( g ) = acceleration due to gravity (9.8 m/s²) ( \mu_k ) = kinetic friction coefficient (3)

Substitute the values into the formula and calculate:

[ F = 5 \cdot (6 + 9.8 \cdot 3) ]

Calculate to find the force necessary.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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