An object with a mass of #5 kg# is hanging from a spring with a constant of #3 (kg)/s^2#. If the spring is stretched by #2 m#, what is the net force on the object?

Answer 1

#vec F_(n et)=44N#

As the ball is pulled by a distance #x#, a restoring force #vec F_(spri ng)=kx# acts on the ball and pulls it in the upward direction.

The weight of the ball #mvec g# acts in the downward direction.

Therefore the net force

#" "vec F_(n et)=mvec g-vec F_(spri ng)#

#rArr" "vec F_(n et)=mvec g-kx#

#rArr" "vec F_(n et)=5xx10-3xx2#

#rArr" "vec F_(n et)=44N#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Xavier Adame

The net force on the object is 30 N.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.