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An object with a mass of #4 kg# is revolving around a point at a distance of #5 m#. If the object is making revolutions at a frequency of #5 Hz#, what is the centripetal force acting on the object?

Answer 1

Charles Aeschliman

The centripetal force is #=19.739kN#

Centripetal force is what

#F=mv^2/r=mr omega^2#

The mass is #m=4kg#

The radius is #r=5m#

The angular velocity is #omega=2pif=10pi#

Consequently,

#F=4*5*(10pi)^2=19739N#

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Answer 2

Elena Albarran

Centripetal force is #19739.21N#

Centripetal force acting on a body in circular motion is given by

#F_c=(mv^2)/r#, where#m# is mass, #v# is velocity and #r# is the radius

As object moves at a frequency of #fHz#, it means it moves

#2pirxxf# in #1# second and hence #v=2pirf#

and #F_c=m/rxx4pi^2r^2f^2=4pi^2mrf^2#

aas #m=4kg#, #f=5Hz# and #r=5m#

#F_c=4pi^2xx4xx5xx5^2=2000pi^2=19739.21N#

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Answer 3

Adrian Ayala

The centripetal force acting on the object is 500 N.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.