# An object with a mass of #4 kg# is revolving around a point at a distance of #2 m#. If the object is making revolutions at a frequency of #9 Hz#, what is the centripetal force acting on the object?

The centripetal force is

Centripetal force is what

The object's mass is

The circle's radius is

The rotational frequency is

The velocity of angular motion is

Omega = 2pif = 2*pi * 9 = 19pirads^-1#

Consequently,

Centripetal force is what

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The centripetal force acting on the object can be calculated using the formula:

[ F = m \times r \times (2\pi f)^2 ]

Where:

- ( F ) is the centripetal force,
- ( m ) is the mass of the object,
- ( r ) is the radius of the circular path, and
- ( f ) is the frequency of revolution.

Given ( m = 4 , \text{kg} ), ( r = 2 , \text{m} ), and ( f = 9 , \text{Hz} ), we can plug these values into the formula:

[ F = 4 \times 2 \times (2\pi \times 9)^2 ]

[ F = 4 \times 2 \times (18\pi)^2 ]

[ F = 4 \times 2 \times 324\pi^2 ]

[ F ≈ 8,208\pi^2 , \text{N} ]

So, the centripetal force acting on the object is approximately ( 8,208\pi^2 , \text{N} ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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