An object with a mass of #4 kg# is moving at #7 m/s# over a surface with a kinetic friction coefficient of #3 #. How much power will it take to accelerate the object at #4 m/s^2?

Answer 1

#952 W#

Clearly,here certain amount of force(#F#) will be required to overcome the frictional force acting at the interface of the object and the surface and then will impart an acceleration(#a#) of #4m/s^2#
Now,here frictional force(#f#) acting is #mu×N# =#mu×mg# i.e #120 N# (#mu# is the coefficient of kinetic friction)

So, from equation of force,we can write,

#F-f=m×a#
Putting the values we get, # F=136 N#
Now,considering that,after application of this force for certain time,the object will attain a velocity(#v#) of #7 m/s# from rest.
So, power required = #F×v# i.e #952 W#
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Answer 2

The power required to accelerate the object at 4 m/s^2 is 28 watts.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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