# An object with a mass of #4 kg# is hanging from a spring with a constant of #3 (kg)/s^2#. If the spring is stretched by # 6 m#, what is the net force on the object?

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The net force acting on the object can be calculated using Hooke's Law:

[ F = kx ]

where:

- ( F ) is the force,
- ( k ) is the spring constant, given as ( 3 ) (kg)/s(^2),
- ( x ) is the displacement, which is ( 6 ) m.

Plugging in the values:

[ F = (3)(6) ]

[ F = 18 ]

Therefore, the net force acting on the object is ( 18 ) Newtons.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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