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An object with a mass of #2# # kg# is revolving around a point at a distance of #7# #m#. If the object is making revolutions at a frequency of #13# # Hz#, what is the centripetal force acting on the object?

Answer 1

Emily Abbate

#F =mr\omega^2 =2xx7xx(13xx2\pi)^2 =93 405# #N#

The centripetal force is given by:

#F=mr\omega^2#

where #r# is the radius, #m# is the mass and #\omega# is the rotational frequency in #rads^-1#.

To convert a frequency in #Hz# to #rads^-1# we multiply by #2\pi#.

Therefore #F =mr\omega^2 =2xx7xx(13xx2\pi)^2 =93 405# #N#

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Answer 2

Axel Acevedo

The centripetal force acting on the object is 364 N.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.