Home > Physics > Circular Motion

An object with a mass of #2 kg# is revolving around a point at a distance of #7 m#. If the object is making revolutions at a frequency of #5 Hz#, what is the centripetal force acting on the object?

Answer 1

Elena Albarran

The centripetal force is #=13817.4N#

The centripetal force is

#F=mromega^2#

The mass of the object is #m=2kg#

The radius of the circle is #r=7m#

The frequency is #f=5Hz#

The angular velocity is #omega=2pif=2*pi*5=10pirads^-1#

The centripetal force is

#F=2*7*(10pi)^2=13817.4N#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Emily Abbate

The centripetal force acting on the object can be calculated using the formula ( F = m \times (2\pi f)^2 \times r ), where ( F ) is the centripetal force, ( m ) is the mass of the object (2 kg), ( f ) is the frequency of revolutions (5 Hz), and ( r ) is the radius of the circular path (7 m).

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.