Home > Physics > Circular Motion

An object with a mass of #2 kg# is revolving around a point at a distance of #7 m#. If the object is making revolutions at a frequency of #2 Hz#, what is the centripetal force acting on the object?

Answer 1

Sebastian Acosta

I found: #2210.79N#

Have a look:

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Adam Arnold

The centripetal force acting on the object is ( F = m \cdot r \cdot (2\pi f)^2 ), where ( m = 2 ) kg (mass of the object), ( r = 7 ) m (distance from the center), and ( f = 2 ) Hz (frequency of revolutions).

Substituting the values:

( F = 2 \times 7 \times (2\pi \times 2)^2 )

( F = 2 \times 7 \times (4\pi)^2 )

( F = 2 \times 7 \times 16\pi^2 )

( F = 224\pi^2 ) N

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.