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An object with a mass of #2 kg# is revolving around a point at a distance of #5 m#. If the object is making revolutions at a frequency of #7 Hz#, what is the centripetal force acting on the object?

Answer 1

Charlotte Aaron

The centripetal force is #=19.34kN#

The centripetal force is given by the formula

#F=mv^2/r=mr omega^2#

The mass of the object is #m=2kg#

The radius is #r=5m#

The frequency is #f=7Hz#

The angular velocity is #omega=2pif=2*7*pi=14pirads^-1#

The centripetal force is

#F=2*5*(14pi)^2=19344.4N=19.34kN#

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Answer 2

Nicholas Agrusa

The centripetal force acting on the object is ( F = m \cdot r \cdot \omega^2 ), where ( m ) is the mass of the object, ( r ) is the distance from the center of rotation, and ( \omega ) is the angular velocity. Given that the mass ( m = 2 ) kg, the distance ( r = 5 ) m, and the frequency ( f = 7 ) Hz, the angular velocity ( \omega ) can be calculated using the formula ( \omega = 2 \pi f ). Substituting the values, we get ( \omega = 2 \pi \times 7 ) rad/s. Then, ( F = 2 \times 5 \times (2 \pi \times 7)^2 ) N. After calculating, the centripetal force is approximately 615.75 N.

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Answer from HIX Tutor

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