# An object with a mass of #2 kg# is revolving around a point at a distance of #5 m#. If the object is revolving at a rate of #5 Hz#, what is the centripetal force on the object?

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The general expression for a centripetal force can now be used:

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Centripetal force = ( m \cdot r \cdot (\omega)^2 ) Where: ( m = 2 , \text{kg} ) ( r = 5 , \text{m} ) ( \omega = 2 \pi \cdot \text{frequency} )

Centripetal force = ( 2 \cdot 5 \cdot (2 \pi \cdot 5)^2 )

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- What is difference between the gravitational force and the force of gravity?
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