An object with a mass of #2 kg# is revolving around a point at a distance of #5 m#. If the object is revolving at a rate of #3 Hz#, what is the centripetal force on the object?

Answer 1

#F_c = 3.6N#

The formula for centripetal force is, #F_c = mv^2 /r#
#m = 2k_g# #v = 3ms^-1#, because #1H_z = 1sec# #r = 5m#
#= 2 3^2/5#
# = 3.6N#
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Answer 2

The centripetal force (( F_c )) acting on the object can be calculated using the formula:

[ F_c = m \cdot r \cdot \omega^2 ]

Where: ( m ) = mass of the object (2 kg), ( r ) = radius of the circular motion (5 m), ( \omega ) = angular frequency (2π times the given frequency).

Substitute the values into the formula and calculate ( F_c ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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