An object with a mass of #2 kg# is on a surface with a kinetic friction coefficient of # 2 #. How much force is necessary to accelerate the object horizontally at #8 m/s^2#?

Answer 1

#"55.2 N"#

Using a smooth surface and Newton's second law

#"F = ma"#

However, the surface here is not smooth, so more force is needed to offset the frictional effect.

#"F = ma + μmg"#
#"F" = ("2 kg × 8 m/s"^2) + ("2 × 2 kg × 9.8 m/s"^2)#
#"F = 16 N + 39.2 N = 55.2 N"#
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Answer 2

To accelerate the object horizontally at (8 , m/s^2), a net force must be applied. The force required can be calculated using Newton's second law, which states that force ((F)) equals mass ((m)) times acceleration ((a)). The formula is (F = m \times a). Substituting the given values, the force required is (F = 2 , kg \times 8 , m/s^2 = 16 , N).

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Answer 3

The force necessary to accelerate the object horizontally at 8 m/s^2 is 16 Newtons.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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