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An object with a mass of #2 kg# is on a plane with an incline of #pi/12 #. If the object is being pushed up the plane with #7 N # of force, what is the net force on the object?

Answer 1

Julia Aguilar

The net force is #=1.93N#

Taking the direction up and parallel to the plane as positive #↗^+#

Let the force pushing the object be #=F N#

Then the net force on the object is

#=F-Wsintheta#

#=F-mgsintheta#

#=7-2*9.8sin(pi/12)#

#=7-5.07#

#=1.93N#

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Answer 2

Layla Ahmed

The net force on the object is ( F_{\text{net}} = F_{\text{applied}} - F_{\text{gravity}\parallel} ). First, calculate the gravitational force parallel to the incline: ( F_{\text{gravity}\parallel} = mg \sin(\theta) ). ( F_{\text{gravity}\parallel} = (2 , \text{kg})(9.8 , \text{m/s}^2) \sin(\pi/12) \approx 3.27 , \text{N} ). Now, substitute the values into the equation: ( F_{\text{net}} = 7 , \text{N} - 3.27 , \text{N} = 3.73 , \text{N} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.