An object with a mass of #2 kg# is hanging from an axle with a radius of #7 m#. If the wheel attached to the axle has a radius of #14 m#, how much force is needed to raise the object?

Answer 1

The force is #=9.8N#

The load is #L=2gN#

The radius of the axle is #r=7m#

The radius of the wheel is #R=14m#

The effort is #=FN#

The acceleration due to gravity is #g=9.8ms^-2#

Taking moments about the center of the axle

#F*14=2g*7#

#F=(2g*7)/14=9.8N#

The force is #F=9.8N#

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Answer 2

To calculate the force needed to raise the object, we can use the equation: Force = mass * gravitational acceleration * radius of the wheel divided by the radius of the axle.

Using the given values: Mass = 2 kg Gravitational acceleration = 9.8 m/s^2 Radius of the wheel = 14 m Radius of the axle = 7 m

Plugging these values into the equation: Force = (2 kg) * (9.8 m/s^2) * (14 m) / (7 m) = 39.2 N

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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