An object with a mass of #2 kg# is acted on by two forces. The first is #F_1= < 9 N , 5 N># and the second is #F_2 = < 7 N, -6 N>#. What is the object's rate and direction of acceleration?

Answer 1

#a=8.02" "m/s^2#

#F_1=<9,5>" ; "F_2=<7,-6>#

#F_1=9i+5j" ; "F_2=7i-6j#

#vec F_R:"Resultant vector"#

#vec F_R=(9+7)i+(5-6)j#

#vec F_R=16i-j#

#"Magnitude of F_R:"#

#F_R=sqrt(16^2+(-1)^2)#

#F_R=F_"net"=sqrt(256+1)#

#F_"net"=sqrt 257=16.03" N"#

#a:"acceleration of object"#

#a=F_"net"/m#

#a=(16.03)/2#

#a=8.02" "m/s^2#

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Answer 2

To find the acceleration, first calculate the net force by adding the two given forces together. Then, use Newton's second law, F = ma, where F is the net force, m is the mass, and a is the acceleration. Finally, divide the net force by the mass to find the acceleration vector.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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