# An object with a mass of #2 kg# is acted on by two forces. The first is #F_1= < -2 N , 5 N># and the second is #F_2 = < 4 N, -1 N>#. What is the object's rate and direction of acceleration?

The net acceleration is

The resultant force is

We use Newton's secnd Law

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To find the net force acting on the object, add the two given forces:

F_net = F_1 + F_2 = (-2 N, 5 N) + (4 N, -1 N) = (2 N, 4 N)

Next, calculate the acceleration using Newton's second law, F = ma:

F_net = m * a a = F_net / m = (2 N, 4 N) / 2 kg = (1 m/s^2, 2 m/s^2)

So, the object's rate of acceleration is 1 m/s^2 in the x-direction and 2 m/s^2 in the y-direction.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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