Home > Physics > Frictional Forces

An object with a mass of #15 kg# is lying still on a surface and is compressing a horizontal spring by #5/6 m#. If the spring's constant is #15 (kg)/s^2#, what is the minimum value of the surface's coefficient of static friction?

Answer 1

Elena Albarran

#mu=0,085#

#F=u_k*Delta x#

#u_k=15 " "(kg)/s^2#

#Delta x=5/6 " "m#

#F=15*5/6=75/6=25/2" N"#

#F_f=mu* N"( Friction Force)"# #mu:"coefficient of static friction"# #N:"normal force to the contacting surfaces"# #"we can write "N=m*g" (The Newton's third law)"#

#F=F_f# #"m:15 kg"# #25/2=mu*15*9,81#

#25=2*15*9,81* mu#

#25=294,3*mu#

#mu=25/(294,3)#

#mu=0,085#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Charlotte Aaron

The minimum value of the surface's coefficient of static friction is 0.2.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.